https://leetcode.com/problems/count-and-say/description/
My GitHub: Count And Say
- The nth level result is from counting each digit of the result of (n-1) th level.
https://leetcode.com/problems/count-and-say/description/
My GitHub: Count And Say
https://leetcode.com/problems/string-to-integer-atoi/description/
github:
Checking point:
LeetCode: https://leetcode.com/problems/reverse-integer/description/
The below Solution 1 is the most popular solution we can find online.
But here is another way (Solution 2) to solve the problem with StringBuffer.
The Solution 2 is easier to understand and the code is cleaner.
Leetcode: https://leetcode.com/problems/rotate-image/description/
Given input matrix = [1,2,3], [4,5,6], [7,8,9] rotate the input matrix in-place such that it becomes: [7,4,1], [8,5,2], [9,6,3]
Given a non-negative integer represented as a non-empty array of digits, plus one to the integer. You may assume the integer do not contain any leading zero, except the number 0 itself. The digits are stored such that the most significant digit is at the head of the list.
For example:
Q1.
int[] nums = {1,2,3,4};
int[] result = plusOne(nums);
the digits are in the result array are {1,2,3,5};
GitHub:
There are many different solutions, I practiced with a HashSet. Time complexity: O (n).
Given an array of integers that is already sorted in ascending order, find two numbers such that they add up to a specific target number.
CheckPoint: if (numbers != null && numbers.length > 1) {throw new IllegalArgumentException(“No solution!”);}
github:arrayQueue.java.
reuse a fixed size array. —-> Tracking 2 variables frontIndex for deletion and rearIndex for insertion.
github: ImplementQueueusingStacks.java
Using 2 stacks- s1 and s2 to implement a queue.
Purpose: keep the input on the bottom of s1
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